By Alex Bridges -- email@example.com
U.S. Congressman Robert W. "Bob" Goodlatte will run for re-election to the House of Representatives in Virginia's 6th District after defeating challenger Karen U. Kwiatkowski in the Republican Party primary Tuesday.
Unofficial returns posted online by the Virginia State Board of Elections showed Goodlatte received 21,727 votes, or 66.45 percent of the total cast, compared to Kwiatkowski, with 10,968 votes, or 33.54 percent. The state agency calculated that 7.6 percent of the active registered voters cast in the district cast ballots in the primary.
"We're very pleased with the support of the Republican primary voters and we're very pleased we were able to run a positive campaign, from start to finish, and now we look forward to moving into the fall campaign, running on the [Mitt] Romney-[George] Allen-Goodlatte ticket and talking about the issues that face the country related to this administration and their inability to grow the economy, create jobs and reign in the power and spending of federal government," Goodlatte said by telephone after the polls closed.
Goodlatte, 59, has served the 6th District since 1993.
Kwiatkowski, 51, challenged Goodlatte as a constitutional conservative. Kwiatkowski said she regrets the loss but also claims to have sent a message to the Goodlatte campaign.
"We didn't win the vote like we would have liked to have, but we owned Bob Goodlatte," Kwiatkowski said by phone Tuesday night. "We sent a message to him and he has also sent a message back because his radio ads that he was running this past week told everybody in the sixth district that he was gonna cut spending and that he was a Constitutional Conservative. Now where have we heard that before? So we've got him right where we want him."
Unofficial results showed Goodlatte received 813 votes in Warren County or 54.74 percent of the ballots cast, compared to Kwiatkowski, with 672 votes or 45.25 percent of the total. Goodlatte also claimed victory in Shenandoah County where he received 1,393 votes or 60.12 percent, compared to Kwiatkowski, with 924 votes or 39.87 percent.
In his home city of Roanoke, Goodlatte received 1,757 votes, or 70.73 percent of the ballots cast. Kwiatkowski received 727 votes or 29.26 percent of the total, the unofficial returns show.
Goodlatte took 2,457 votes in Rockingham County, or 52.34 percent of the ballots cast, while Kwiatkowski received 2,237 votes or 47.65 percent.
In Page County, Goodlatte claimed a slim majority over Kwiatkowski. Goodlatte received 391 votes, or 50.84 percent of the ballots cast, compared to Kwiatkowski, with 378 votes, or 49.15 percent.
Kwiatkowski won a slim majority in Harrisonburg, the unofficials results showed. With all precincts in Harrisonburg reporting, according to the Virginia State Board of Elections, Kwiatkowski received 616 votes or 50.57 percent, compared to Goodlatte with 602 votes and 49.42 percent.